BernardSmith
Senior Member
I just bought about a gallon of tupelo honey to make some mead. The jar weighs just over 12 lbs (12lbs 2 oz) or 194 ozs. I see that EC Kraus uses a rule of thumb that 3 ozs of honey will produce 1 percent alcohol per 1 gallon (or 18 oz will produce 1 percent in 6 gallons) Dividing 194 by 18 to determine the percentage of alcohol 6 gallons might produce, I get just under 11 or about 10.8 % ABV, so if I am looking for about 12% I should go for 5 gallons (using about 180 ozs: (5 (gals) X 3 (oz) X 12 (percent)) of the honey and holding back about 14 oz to back sweeten ). Does that sound right? Or is this 3 oz = 1 percent rule of thumb not really a rule of thumb I should be using (With table sugar (sucrose) I assume that 2 oz produces 1 percent alcohol per gallon). Thoughts?