Equation for alcohol content

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PeterZ

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ISTR seeing an equation about initial SG - final SG x some factor = alcohol. Does anybody have this equation?
 
Starting SG minus Ending SG Multiplied by 131 will give you ABV
1.090 - .990 = .01 x 131 = 13.1%
 
Yes, and I dont know. This is the way I was taught, Take your initial
SG not usiing decimals 1090, subtract your finished SG 990=100, and
then divide by 7.36. Your alc % =13.58. Which is actually the true way
please.
 
wadewade said:
Yes, and I dont know. This is the way I was taught, Take your initial
SG not usiing decimals 1090, subtract your finished SG 990=100, and
then divide by 7.36. Your alc % =13.58. Which is actually the true way
please.

This is the way I had read to do it too....
 
At least I'm not alone then. Thank you. I figured I was going to be the only loser with the wrong formula.
 
CajunTim said:
What does the 131 represent? Is that for all batch sizes?


Don't have a clue as to what it represents Cajun but it is the formula for whatever size batch you are making.
 
As with all aspects of wine making..there are numerous ways of doing the same task ..All are right and none are wrong. A matter of personal preference. In this case, I can multiply quicker than I can divide
smiley36.gif
 
I dont know about that Waldo. You seem to be able to divide a bottle of wine into one glass very quick.
 
Wade, I measure mine the same way. You are not the only loser with the wrong calculations....
 
http://www.ritchieproducts.co.uk/calculatingABV.htm

From which I gather that....

17 grams of sugar per liter per 1% ABV. 5083 grams to produce 13% in a 6 gallon batch. However, different yeast strains vary from that rough figure because the different strains produce other volatiles in varying quantities so the calculatio. can be + or - .3% ABV depending on the yeast strain.
 
This is the one I used. It came off a sitefrom roger.simmondsfor homemade wine making for beginners.





Firstly find the degrees of gravity lost by deducting the final s.g from the initial s.g. Ignore the decimal point.


Next you will need to select a factor from the table below. The factor is determined by the original s.g.
<CENTER>
<TABLE cellSpacing=20>
<T>
<TR>
<TD>
<TABLE border=1>
<T>
<TR align=middle>
<TH>Original s.g.</TH>
<TH>Factor
<TR align=middle>
<TD>1.160</TD>
<TD>6.82
<TR align=middle>
<TD>1.150</TD>
<TD>6.84
<TR align=middle>
<TD>1.140</TD>
<TD>6.87
<TR align=middle>
<TD>1.130</TD>
<TD>6.90
<TR align=middle>
<TD>1.120</TD>
<TD>6.93
<TR align=middle>
<TD>1.110</TD>
<TD>6.96
<TR align=middle>
<TD>1.100</TD>
<TD>7.00
<TR align=middle>
<TD>1.090</TD>
<TD>7.04 </TD></TR></T></TABLE>
<TD>
<TABLE border=1>
<T>
<TR align=middle>
<TH>Original s.g.</TH>
<TH>Factor
<TR align=middle>
<TD>1.080</TD>
<TD>7.09
<TR align=middle>
<TD>1.070</TD>
<TD>7.14
<TR align=middle>
<TD>1.060</TD>
<TD>7.20
<TR align=middle>
<TD>1.050</TD>
<TD>7.29
<TR align=middle>
<TD>1.040</TD>
<TD>7.39
<TR align=middle>
<TD>1.030</TD>
<TD>7.45
<TR align=middle>
<TD>1.020</TD>
<TD>7.52
<TR align=middle>
<TD>1.010</TD>
<TD>7.59 </TD></TR></T></TABLE></TD></TR></T></TABLE></CENTER>Finally you need to devide the degrees of gravity lost by the factor to find the percentage of alcohol by volume.


As an example; original s.g is 1.110, final s.g. is 1.004
Degrees lost (ignoring decimal) = 1110 - 1004 = 106
Percentage alcohol by volume = 106/6.96 = 15.23%
 
AHHHHHHHHHHHHHHHH!!


three different methods, three different results


S SG 1.090
E SG 0.990


Method 1 1090 - 990 = 100
100 / 7.36 = 13.6%


Method 2 1.090 - .990 = .1
.1 * 131 = 13.1%


Method 3 1090 - 990 = 100
100 / 7.04 = 14.2%
 
Coaster said:
AHHHHHHHHHHHHHHHH!!
 
three different methods, three different results
 
S SG 1.090
E SG 0.990
 
Method 1 1090 - 990 = 100
100 / 7.36 = 13.6%
 
Method 2 1.090 - .990 = .1
.1 * 131 = 13.1%
 
Method 3 1090 - 990 = 100
100 / 7.04 = 14.2% 

Now I am really confused
smiley5.gif
 
Now I am really confused
smiley5.gif
[/QUOTE]



That makes two of us.
smiley29.gif
I wonder which one is closest to an alcohol tester?
 
get a gas spectrometer (anything from $2,000 - $20,000 and you should be able to get accurately enough (of course you need the Ph.D. as well)
 
1.090-.990 X 1000 X .129 = 12.9
no wonder my wines are weak, I'm using the wrong formula..lol
 
If you want to know the exact alcohol content of your wine you will need to spend a few hundred dollars and purchase an Ebulliometer. If you are not a commercial winery, exact is not necessary. To obtain a ballpark idea of alcohol content, any of the many formulas or tables available to home winemakers will do.<?:namespace prefix = o ns = "urn:schemas-microsoft-com:eek:ffice:eek:ffice" />

For those interested in yet another formula for calculating potential alcohol, I present the following for your entertainment and amusement. The formula is based on the work of Bryan Acton and Peter Duncan and is from their book <I style="mso-bidi-font-style: normal">Progressive Winemaking[/I]. This is the only formula I am aware of that makes the claim of being within plus or minus 0.5% of an Ebulliometer. This claim is for wines with an alcohol content of 10% to 14%.

ABV (Alcohol by Volume) = (OG – FG) / (7.75 – (3 * ((OG – FG – AG) / 800)))

Where:
OG = Original Specific Gravity times 1000 (i.e. 1.100 * 1000 = 1100)
FG = Final Specific Gravity times 1000
AG = Gravity adjustment. This is an adjustment to correct for the non-sugar solutes in the juice or wine. The authors state that the correction is usually between specific gravity 0.005 and 0.010. They recommend using 0.007. This number is also multiplied by 1000.

Example:

OG = 1100 (Original Specific Gravity of 1.100 * 1000)
FG = 1000 (Final Specific Gravity of 1.000 * 1000)
AG = 7 (the recommended 0.007 * 1000)

PA = (1100 – 1000) / (7.75 – (3 * ((1100 – 1000 -7) / 800)))
= (100) / (7.75 – (3* (93 / 800)))
= 100 / (7.75 – (3 * 0.116))
= 100 / (7.75 – 0.349)
= 100 / 7.40
= 13.51% ABV

If you repeat the above calculation with a final gravity of 0.990, the result will be 110 / 7.36 (Wade, does this denominator look familiar?) or 14.9% ABV.

I hope I got it right. Have fun!
 

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