Specific gravity

Winemaking Talk - Winemaking Forum

Help Support Winemaking Talk - Winemaking Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

scotty

Senior Member
Joined
Jun 11, 2006
Messages
1,423
Reaction score
2
If i make what i call a standard sugar syrup.
500ml sugar disolved in 250ml water and lightly boiled untill clear--maybe 8-10 minutes.
Then after it cools i add a measured amount of the syrup to 3 timesthat amountof water, Will i get the SG of the sugar syrup if i multiply the reading by 3.


I will try it with 4 times the amount in water till i get the sg into the hydrometer range if this is a valid way to determine the SG of the undiluted sugar syrup.
smiley1.gif
 
Scotty, the sg of the syrup is some number greater than 1.000. Water (at 68F) is 1.000 by definition. If you dilute the syrup with 2 parts water the sg will be:

diluted(sg) = ( [original(sg) - 1] / 3 ) + 1

because it is 1/3 syrup.

For 1 part syrup + 3 parts water:

diluted(sg) = ( [original(sg) - 1] / 4 ) + 1

because it is 1/4 syrup.

And so on, and so on, and so on...
 
PeterZ said:
Scotty, the sg of the syrup is some number greater than 1.000. Water (at 68F) is 1.000 by definition. If you dilute the syrup with 2 parts water the sg will be:

diluted(sg) = ( [original(sg) - 1] / 3 ) + 1

because it is 1/3 syrup.

For 1 part syrup + 3 parts water:

diluted(sg) = ( [original(sg) - 1] / 4 ) + 1

because it is 1/4 syrup.

And so on, and so on, and so on...


Thanks pete. I was going to do it in reverse tomorrow to see the relationship. I'm just curious when I see these things
 
Back
Top