[scotty]

If i make what i call a standard sugar syrup.
500ml sugar disolved in 250ml water and lightly boiled untill clear--maybe 8-10 minutes.
Then after it cools i add a measured amount of the syrup to 3 timesthat amountof water, Will i get the SG of the sugar syrup if i multiply the reading by 3.


I will try it with 4 times the amount in water till i get the sg into the hydrometer range if this is a valid way to determine the SG of the undiluted sugar syrup.

[PeterZ]

Scotty, the sg of the syrup is some number greater than 1.000. Water (at 68F) is 1.000 by definition. If you dilute the syrup with 2 parts water the sg will be:

diluted(sg) = ( [original(sg) - 1] / 3 ) + 1

because it is 1/3 syrup.

For 1 part syrup + 3 parts water:

diluted(sg) = ( [original(sg) - 1] / 4 ) + 1

because it is 1/4 syrup.

And so on, and so on, and so on...

[scotty]

Originally Posted by PeterZ

Scotty, the sg of the syrup is some number greater than 1.000. Water (at 68F) is 1.000 by definition. If you dilute the syrup with 2 parts water the sg will be:

diluted(sg) = ( [original(sg) - 1] / 3 ) + 1

because it is 1/3 syrup.

For 1 part syrup + 3 parts water:

diluted(sg) = ( [original(sg) - 1] / 4 ) + 1

because it is 1/4 syrup.

And so on, and so on, and so on...

Thanks pete. I was going to do it in reverse tomorrow to see the relationship. I'm just curious when I see these things